3.429 \(\int x^2 (a+b \log (c (d+\frac {e}{\sqrt {x}})^n))^2 \, dx\)

Optimal. Leaf size=404 \[ \frac {2 b e^6 n \log \left (1-\frac {d}{d+\frac {e}{\sqrt {x}}}\right ) \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{3 d^6}+\frac {2 b e^5 n \sqrt {x} \left (d+\frac {e}{\sqrt {x}}\right ) \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{3 d^6}-\frac {b e^4 n x \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{3 d^4}+\frac {2 b e^3 n x^{3/2} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{9 d^3}-\frac {b e^2 n x^2 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{6 d^2}+\frac {2 b e n x^{5/2} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{15 d}+\frac {1}{3} x^3 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )^2-\frac {2 b^2 e^6 n^2 \text {Li}_2\left (\frac {d}{d+\frac {e}{\sqrt {x}}}\right )}{3 d^6}+\frac {77 b^2 e^6 n^2 \log \left (d+\frac {e}{\sqrt {x}}\right )}{90 d^6}+\frac {137 b^2 e^6 n^2 \log (x)}{180 d^6}-\frac {77 b^2 e^5 n^2 \sqrt {x}}{90 d^5}+\frac {47 b^2 e^4 n^2 x}{180 d^4}-\frac {b^2 e^3 n^2 x^{3/2}}{10 d^3}+\frac {b^2 e^2 n^2 x^2}{30 d^2} \]

[Out]

47/180*b^2*e^4*n^2*x/d^4-1/10*b^2*e^3*n^2*x^(3/2)/d^3+1/30*b^2*e^2*n^2*x^2/d^2+137/180*b^2*e^6*n^2*ln(x)/d^6+7
7/90*b^2*e^6*n^2*ln(d+e/x^(1/2))/d^6-1/3*b*e^4*n*x*(a+b*ln(c*(d+e/x^(1/2))^n))/d^4+2/9*b*e^3*n*x^(3/2)*(a+b*ln
(c*(d+e/x^(1/2))^n))/d^3-1/6*b*e^2*n*x^2*(a+b*ln(c*(d+e/x^(1/2))^n))/d^2+2/15*b*e*n*x^(5/2)*(a+b*ln(c*(d+e/x^(
1/2))^n))/d+2/3*b*e^6*n*ln(1-d/(d+e/x^(1/2)))*(a+b*ln(c*(d+e/x^(1/2))^n))/d^6+1/3*x^3*(a+b*ln(c*(d+e/x^(1/2))^
n))^2-2/3*b^2*e^6*n^2*polylog(2,d/(d+e/x^(1/2)))/d^6-77/90*b^2*e^5*n^2*x^(1/2)/d^5+2/3*b*e^5*n*(a+b*ln(c*(d+e/
x^(1/2))^n))*(d+e/x^(1/2))*x^(1/2)/d^6

________________________________________________________________________________________

Rubi [A]  time = 1.01, antiderivative size = 428, normalized size of antiderivative = 1.06, number of steps used = 26, number of rules used = 12, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {2454, 2398, 2411, 2347, 2344, 2301, 2317, 2391, 2314, 31, 2319, 44} \[ \frac {2 b^2 e^6 n^2 \text {PolyLog}\left (2,\frac {e}{d \sqrt {x}}+1\right )}{3 d^6}+\frac {2 b e^3 n x^{3/2} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{9 d^3}-\frac {b e^2 n x^2 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{6 d^2}-\frac {e^6 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )^2}{3 d^6}+\frac {2 b e^6 n \log \left (-\frac {e}{d \sqrt {x}}\right ) \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{3 d^6}+\frac {2 b e^5 n \sqrt {x} \left (d+\frac {e}{\sqrt {x}}\right ) \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{3 d^6}-\frac {b e^4 n x \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{3 d^4}+\frac {2 b e n x^{5/2} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{15 d}+\frac {1}{3} x^3 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )^2-\frac {b^2 e^3 n^2 x^{3/2}}{10 d^3}+\frac {b^2 e^2 n^2 x^2}{30 d^2}-\frac {77 b^2 e^5 n^2 \sqrt {x}}{90 d^5}+\frac {47 b^2 e^4 n^2 x}{180 d^4}+\frac {77 b^2 e^6 n^2 \log \left (d+\frac {e}{\sqrt {x}}\right )}{90 d^6}+\frac {137 b^2 e^6 n^2 \log (x)}{180 d^6} \]

Antiderivative was successfully verified.

[In]

Int[x^2*(a + b*Log[c*(d + e/Sqrt[x])^n])^2,x]

[Out]

(-77*b^2*e^5*n^2*Sqrt[x])/(90*d^5) + (47*b^2*e^4*n^2*x)/(180*d^4) - (b^2*e^3*n^2*x^(3/2))/(10*d^3) + (b^2*e^2*
n^2*x^2)/(30*d^2) + (77*b^2*e^6*n^2*Log[d + e/Sqrt[x]])/(90*d^6) + (2*b*e^5*n*(d + e/Sqrt[x])*Sqrt[x]*(a + b*L
og[c*(d + e/Sqrt[x])^n]))/(3*d^6) - (b*e^4*n*x*(a + b*Log[c*(d + e/Sqrt[x])^n]))/(3*d^4) + (2*b*e^3*n*x^(3/2)*
(a + b*Log[c*(d + e/Sqrt[x])^n]))/(9*d^3) - (b*e^2*n*x^2*(a + b*Log[c*(d + e/Sqrt[x])^n]))/(6*d^2) + (2*b*e*n*
x^(5/2)*(a + b*Log[c*(d + e/Sqrt[x])^n]))/(15*d) - (e^6*(a + b*Log[c*(d + e/Sqrt[x])^n])^2)/(3*d^6) + (x^3*(a
+ b*Log[c*(d + e/Sqrt[x])^n])^2)/3 + (2*b*e^6*n*(a + b*Log[c*(d + e/Sqrt[x])^n])*Log[-(e/(d*Sqrt[x]))])/(3*d^6
) + (137*b^2*e^6*n^2*Log[x])/(180*d^6) + (2*b^2*e^6*n^2*PolyLog[2, 1 + e/(d*Sqrt[x])])/(3*d^6)

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 44

Int[((a_) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*
x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, 0] && IntegerQ[n] &&  !(IGtQ[n, 0] && L
tQ[m + n + 2, 0])

Rule 2301

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))/(x_), x_Symbol] :> Simp[(a + b*Log[c*x^n])^2/(2*b*n), x] /; FreeQ[{a
, b, c, n}, x]

Rule 2314

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*((d_) + (e_.)*(x_)^(r_.))^(q_), x_Symbol] :> Simp[(x*(d + e*x^r)^(q
+ 1)*(a + b*Log[c*x^n]))/d, x] - Dist[(b*n)/d, Int[(d + e*x^r)^(q + 1), x], x] /; FreeQ[{a, b, c, d, e, n, q,
r}, x] && EqQ[r*(q + 1) + 1, 0]

Rule 2317

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)/((d_) + (e_.)*(x_)), x_Symbol] :> Simp[(Log[1 + (e*x)/d]*(a +
b*Log[c*x^n])^p)/e, x] - Dist[(b*n*p)/e, Int[(Log[1 + (e*x)/d]*(a + b*Log[c*x^n])^(p - 1))/x, x], x] /; FreeQ[
{a, b, c, d, e, n}, x] && IGtQ[p, 0]

Rule 2319

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((d_) + (e_.)*(x_))^(q_.), x_Symbol] :> Simp[((d + e*x)^(q + 1
)*(a + b*Log[c*x^n])^p)/(e*(q + 1)), x] - Dist[(b*n*p)/(e*(q + 1)), Int[((d + e*x)^(q + 1)*(a + b*Log[c*x^n])^
(p - 1))/x, x], x] /; FreeQ[{a, b, c, d, e, n, p, q}, x] && GtQ[p, 0] && NeQ[q, -1] && (EqQ[p, 1] || (Integers
Q[2*p, 2*q] &&  !IGtQ[q, 0]) || (EqQ[p, 2] && NeQ[q, 1]))

Rule 2344

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)/((x_)*((d_) + (e_.)*(x_))), x_Symbol] :> Dist[1/d, Int[(a + b*
Log[c*x^n])^p/x, x], x] - Dist[e/d, Int[(a + b*Log[c*x^n])^p/(d + e*x), x], x] /; FreeQ[{a, b, c, d, e, n}, x]
&& IGtQ[p, 0]

Rule 2347

Int[(((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((d_) + (e_.)*(x_))^(q_))/(x_), x_Symbol] :> Dist[1/d, Int[((
d + e*x)^(q + 1)*(a + b*Log[c*x^n])^p)/x, x], x] - Dist[e/d, Int[(d + e*x)^q*(a + b*Log[c*x^n])^p, x], x] /; F
reeQ[{a, b, c, d, e, n}, x] && IGtQ[p, 0] && LtQ[q, -1] && IntegerQ[2*q]

Rule 2391

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> -Simp[PolyLog[2, -(c*e*x^n)]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]

Rule 2398

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_)*((f_.) + (g_.)*(x_))^(q_.), x_Symbol] :> Simp[((
f + g*x)^(q + 1)*(a + b*Log[c*(d + e*x)^n])^p)/(g*(q + 1)), x] - Dist[(b*e*n*p)/(g*(q + 1)), Int[((f + g*x)^(q
+ 1)*(a + b*Log[c*(d + e*x)^n])^(p - 1))/(d + e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n, q}, x] && NeQ[e*
f - d*g, 0] && GtQ[p, 0] && NeQ[q, -1] && IntegersQ[2*p, 2*q] && ( !IGtQ[q, 0] || (EqQ[p, 2] && NeQ[q, 1]))

Rule 2411

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_.) + (g_.)*(x_))^(q_.)*((h_.) + (i_.)*(x_))
^(r_.), x_Symbol] :> Dist[1/e, Subst[Int[((g*x)/e)^q*((e*h - d*i)/e + (i*x)/e)^r*(a + b*Log[c*x^n])^p, x], x,
d + e*x], x] /; FreeQ[{a, b, c, d, e, f, g, h, i, n, p, q, r}, x] && EqQ[e*f - d*g, 0] && (IGtQ[p, 0] || IGtQ[
r, 0]) && IntegerQ[2*r]

Rule 2454

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))^(q_.)*(x_)^(m_.), x_Symbol] :> Dist[1/n, Subst[I
nt[x^(Simplify[(m + 1)/n] - 1)*(a + b*Log[c*(d + e*x)^p])^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, e, m, n, p,
q}, x] && IntegerQ[Simplify[(m + 1)/n]] && (GtQ[(m + 1)/n, 0] || IGtQ[q, 0]) &&  !(EqQ[q, 1] && ILtQ[n, 0] &&
IGtQ[m, 0])

Rubi steps

\begin {align*} \int x^2 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )^2 \, dx &=-\left (2 \operatorname {Subst}\left (\int \frac {\left (a+b \log \left (c (d+e x)^n\right )\right )^2}{x^7} \, dx,x,\frac {1}{\sqrt {x}}\right )\right )\\ &=\frac {1}{3} x^3 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )^2-\frac {1}{3} (2 b e n) \operatorname {Subst}\left (\int \frac {a+b \log \left (c (d+e x)^n\right )}{x^6 (d+e x)} \, dx,x,\frac {1}{\sqrt {x}}\right )\\ &=\frac {1}{3} x^3 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )^2-\frac {1}{3} (2 b n) \operatorname {Subst}\left (\int \frac {a+b \log \left (c x^n\right )}{x \left (-\frac {d}{e}+\frac {x}{e}\right )^6} \, dx,x,d+\frac {e}{\sqrt {x}}\right )\\ &=\frac {1}{3} x^3 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )^2-\frac {(2 b n) \operatorname {Subst}\left (\int \frac {a+b \log \left (c x^n\right )}{\left (-\frac {d}{e}+\frac {x}{e}\right )^6} \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{3 d}+\frac {(2 b e n) \operatorname {Subst}\left (\int \frac {a+b \log \left (c x^n\right )}{x \left (-\frac {d}{e}+\frac {x}{e}\right )^5} \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{3 d}\\ &=\frac {2 b e n x^{5/2} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{15 d}+\frac {1}{3} x^3 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )^2+\frac {(2 b e n) \operatorname {Subst}\left (\int \frac {a+b \log \left (c x^n\right )}{\left (-\frac {d}{e}+\frac {x}{e}\right )^5} \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{3 d^2}-\frac {\left (2 b e^2 n\right ) \operatorname {Subst}\left (\int \frac {a+b \log \left (c x^n\right )}{x \left (-\frac {d}{e}+\frac {x}{e}\right )^4} \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{3 d^2}-\frac {\left (2 b^2 e n^2\right ) \operatorname {Subst}\left (\int \frac {1}{x \left (-\frac {d}{e}+\frac {x}{e}\right )^5} \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{15 d}\\ &=-\frac {b e^2 n x^2 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{6 d^2}+\frac {2 b e n x^{5/2} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{15 d}+\frac {1}{3} x^3 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )^2-\frac {\left (2 b e^2 n\right ) \operatorname {Subst}\left (\int \frac {a+b \log \left (c x^n\right )}{\left (-\frac {d}{e}+\frac {x}{e}\right )^4} \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{3 d^3}+\frac {\left (2 b e^3 n\right ) \operatorname {Subst}\left (\int \frac {a+b \log \left (c x^n\right )}{x \left (-\frac {d}{e}+\frac {x}{e}\right )^3} \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{3 d^3}-\frac {\left (2 b^2 e n^2\right ) \operatorname {Subst}\left (\int \left (-\frac {e^5}{d (d-x)^5}-\frac {e^5}{d^2 (d-x)^4}-\frac {e^5}{d^3 (d-x)^3}-\frac {e^5}{d^4 (d-x)^2}-\frac {e^5}{d^5 (d-x)}-\frac {e^5}{d^5 x}\right ) \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{15 d}+\frac {\left (b^2 e^2 n^2\right ) \operatorname {Subst}\left (\int \frac {1}{x \left (-\frac {d}{e}+\frac {x}{e}\right )^4} \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{6 d^2}\\ &=-\frac {2 b^2 e^5 n^2 \sqrt {x}}{15 d^5}+\frac {b^2 e^4 n^2 x}{15 d^4}-\frac {2 b^2 e^3 n^2 x^{3/2}}{45 d^3}+\frac {b^2 e^2 n^2 x^2}{30 d^2}+\frac {2 b^2 e^6 n^2 \log \left (d+\frac {e}{\sqrt {x}}\right )}{15 d^6}+\frac {2 b e^3 n x^{3/2} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{9 d^3}-\frac {b e^2 n x^2 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{6 d^2}+\frac {2 b e n x^{5/2} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{15 d}+\frac {1}{3} x^3 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )^2+\frac {b^2 e^6 n^2 \log (x)}{15 d^6}+\frac {\left (2 b e^3 n\right ) \operatorname {Subst}\left (\int \frac {a+b \log \left (c x^n\right )}{\left (-\frac {d}{e}+\frac {x}{e}\right )^3} \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{3 d^4}-\frac {\left (2 b e^4 n\right ) \operatorname {Subst}\left (\int \frac {a+b \log \left (c x^n\right )}{x \left (-\frac {d}{e}+\frac {x}{e}\right )^2} \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{3 d^4}+\frac {\left (b^2 e^2 n^2\right ) \operatorname {Subst}\left (\int \left (\frac {e^4}{d (d-x)^4}+\frac {e^4}{d^2 (d-x)^3}+\frac {e^4}{d^3 (d-x)^2}+\frac {e^4}{d^4 (d-x)}+\frac {e^4}{d^4 x}\right ) \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{6 d^2}-\frac {\left (2 b^2 e^3 n^2\right ) \operatorname {Subst}\left (\int \frac {1}{x \left (-\frac {d}{e}+\frac {x}{e}\right )^3} \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{9 d^3}\\ &=-\frac {3 b^2 e^5 n^2 \sqrt {x}}{10 d^5}+\frac {3 b^2 e^4 n^2 x}{20 d^4}-\frac {b^2 e^3 n^2 x^{3/2}}{10 d^3}+\frac {b^2 e^2 n^2 x^2}{30 d^2}+\frac {3 b^2 e^6 n^2 \log \left (d+\frac {e}{\sqrt {x}}\right )}{10 d^6}-\frac {b e^4 n x \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{3 d^4}+\frac {2 b e^3 n x^{3/2} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{9 d^3}-\frac {b e^2 n x^2 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{6 d^2}+\frac {2 b e n x^{5/2} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{15 d}+\frac {1}{3} x^3 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )^2+\frac {3 b^2 e^6 n^2 \log (x)}{20 d^6}-\frac {\left (2 b e^4 n\right ) \operatorname {Subst}\left (\int \frac {a+b \log \left (c x^n\right )}{\left (-\frac {d}{e}+\frac {x}{e}\right )^2} \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{3 d^5}+\frac {\left (2 b e^5 n\right ) \operatorname {Subst}\left (\int \frac {a+b \log \left (c x^n\right )}{x \left (-\frac {d}{e}+\frac {x}{e}\right )} \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{3 d^5}-\frac {\left (2 b^2 e^3 n^2\right ) \operatorname {Subst}\left (\int \left (-\frac {e^3}{d (d-x)^3}-\frac {e^3}{d^2 (d-x)^2}-\frac {e^3}{d^3 (d-x)}-\frac {e^3}{d^3 x}\right ) \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{9 d^3}+\frac {\left (b^2 e^4 n^2\right ) \operatorname {Subst}\left (\int \frac {1}{x \left (-\frac {d}{e}+\frac {x}{e}\right )^2} \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{3 d^4}\\ &=-\frac {47 b^2 e^5 n^2 \sqrt {x}}{90 d^5}+\frac {47 b^2 e^4 n^2 x}{180 d^4}-\frac {b^2 e^3 n^2 x^{3/2}}{10 d^3}+\frac {b^2 e^2 n^2 x^2}{30 d^2}+\frac {47 b^2 e^6 n^2 \log \left (d+\frac {e}{\sqrt {x}}\right )}{90 d^6}+\frac {2 b e^5 n \left (d+\frac {e}{\sqrt {x}}\right ) \sqrt {x} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{3 d^6}-\frac {b e^4 n x \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{3 d^4}+\frac {2 b e^3 n x^{3/2} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{9 d^3}-\frac {b e^2 n x^2 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{6 d^2}+\frac {2 b e n x^{5/2} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{15 d}+\frac {1}{3} x^3 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )^2+\frac {47 b^2 e^6 n^2 \log (x)}{180 d^6}+\frac {\left (2 b e^5 n\right ) \operatorname {Subst}\left (\int \frac {a+b \log \left (c x^n\right )}{-\frac {d}{e}+\frac {x}{e}} \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{3 d^6}-\frac {\left (2 b e^6 n\right ) \operatorname {Subst}\left (\int \frac {a+b \log \left (c x^n\right )}{x} \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{3 d^6}+\frac {\left (b^2 e^4 n^2\right ) \operatorname {Subst}\left (\int \left (\frac {e^2}{d (d-x)^2}+\frac {e^2}{d^2 (d-x)}+\frac {e^2}{d^2 x}\right ) \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{3 d^4}-\frac {\left (2 b^2 e^5 n^2\right ) \operatorname {Subst}\left (\int \frac {1}{-\frac {d}{e}+\frac {x}{e}} \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{3 d^6}\\ &=-\frac {77 b^2 e^5 n^2 \sqrt {x}}{90 d^5}+\frac {47 b^2 e^4 n^2 x}{180 d^4}-\frac {b^2 e^3 n^2 x^{3/2}}{10 d^3}+\frac {b^2 e^2 n^2 x^2}{30 d^2}+\frac {77 b^2 e^6 n^2 \log \left (d+\frac {e}{\sqrt {x}}\right )}{90 d^6}+\frac {2 b e^5 n \left (d+\frac {e}{\sqrt {x}}\right ) \sqrt {x} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{3 d^6}-\frac {b e^4 n x \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{3 d^4}+\frac {2 b e^3 n x^{3/2} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{9 d^3}-\frac {b e^2 n x^2 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{6 d^2}+\frac {2 b e n x^{5/2} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{15 d}-\frac {e^6 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )^2}{3 d^6}+\frac {1}{3} x^3 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )^2+\frac {2 b e^6 n \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right ) \log \left (-\frac {e}{d \sqrt {x}}\right )}{3 d^6}+\frac {137 b^2 e^6 n^2 \log (x)}{180 d^6}-\frac {\left (2 b^2 e^6 n^2\right ) \operatorname {Subst}\left (\int \frac {\log \left (1-\frac {x}{d}\right )}{x} \, dx,x,d+\frac {e}{\sqrt {x}}\right )}{3 d^6}\\ &=-\frac {77 b^2 e^5 n^2 \sqrt {x}}{90 d^5}+\frac {47 b^2 e^4 n^2 x}{180 d^4}-\frac {b^2 e^3 n^2 x^{3/2}}{10 d^3}+\frac {b^2 e^2 n^2 x^2}{30 d^2}+\frac {77 b^2 e^6 n^2 \log \left (d+\frac {e}{\sqrt {x}}\right )}{90 d^6}+\frac {2 b e^5 n \left (d+\frac {e}{\sqrt {x}}\right ) \sqrt {x} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{3 d^6}-\frac {b e^4 n x \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{3 d^4}+\frac {2 b e^3 n x^{3/2} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{9 d^3}-\frac {b e^2 n x^2 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{6 d^2}+\frac {2 b e n x^{5/2} \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )}{15 d}-\frac {e^6 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )^2}{3 d^6}+\frac {1}{3} x^3 \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right )^2+\frac {2 b e^6 n \left (a+b \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )\right ) \log \left (-\frac {e}{d \sqrt {x}}\right )}{3 d^6}+\frac {137 b^2 e^6 n^2 \log (x)}{180 d^6}+\frac {2 b^2 e^6 n^2 \text {Li}_2\left (1+\frac {e}{d \sqrt {x}}\right )}{3 d^6}\\ \end {align*}

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Mathematica [A]  time = 0.27, size = 540, normalized size = 1.34 \[ \frac {60 a^2 d^6 x^3+120 a b d^6 x^3 \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )+24 a b d^5 e n x^{5/2}-30 a b d^4 e^2 n x^2+40 a b d^3 e^3 n x^{3/2}-60 a b d^2 e^4 n x-120 a b e^6 n \log \left (d \sqrt {x}+e\right )+120 a b d e^5 n \sqrt {x}+60 b^2 d^6 x^3 \log ^2\left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )+24 b^2 d^5 e n x^{5/2} \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )-30 b^2 d^4 e^2 n x^2 \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )+40 b^2 d^3 e^3 n x^{3/2} \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )-60 b^2 d^2 e^4 n x \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )-120 b^2 e^6 n \log \left (d \sqrt {x}+e\right ) \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )+120 b^2 d e^5 n \sqrt {x} \log \left (c \left (d+\frac {e}{\sqrt {x}}\right )^n\right )+6 b^2 d^4 e^2 n^2 x^2-18 b^2 d^3 e^3 n^2 x^{3/2}+47 b^2 d^2 e^4 n^2 x-120 b^2 e^6 n^2 \text {Li}_2\left (\frac {\sqrt {x} d}{e}+1\right )+60 b^2 e^6 n^2 \log ^2\left (d \sqrt {x}+e\right )+214 b^2 e^6 n^2 \log \left (d+\frac {e}{\sqrt {x}}\right )+60 b^2 e^6 n^2 \log \left (d \sqrt {x}+e\right )-120 b^2 e^6 n^2 \log \left (d \sqrt {x}+e\right ) \log \left (-\frac {d \sqrt {x}}{e}\right )-154 b^2 d e^5 n^2 \sqrt {x}+107 b^2 e^6 n^2 \log (x)}{180 d^6} \]

Antiderivative was successfully verified.

[In]

Integrate[x^2*(a + b*Log[c*(d + e/Sqrt[x])^n])^2,x]

[Out]

(120*a*b*d*e^5*n*Sqrt[x] - 154*b^2*d*e^5*n^2*Sqrt[x] - 60*a*b*d^2*e^4*n*x + 47*b^2*d^2*e^4*n^2*x + 40*a*b*d^3*
e^3*n*x^(3/2) - 18*b^2*d^3*e^3*n^2*x^(3/2) - 30*a*b*d^4*e^2*n*x^2 + 6*b^2*d^4*e^2*n^2*x^2 + 24*a*b*d^5*e*n*x^(
5/2) + 60*a^2*d^6*x^3 + 214*b^2*e^6*n^2*Log[d + e/Sqrt[x]] + 120*b^2*d*e^5*n*Sqrt[x]*Log[c*(d + e/Sqrt[x])^n]
- 60*b^2*d^2*e^4*n*x*Log[c*(d + e/Sqrt[x])^n] + 40*b^2*d^3*e^3*n*x^(3/2)*Log[c*(d + e/Sqrt[x])^n] - 30*b^2*d^4
*e^2*n*x^2*Log[c*(d + e/Sqrt[x])^n] + 24*b^2*d^5*e*n*x^(5/2)*Log[c*(d + e/Sqrt[x])^n] + 120*a*b*d^6*x^3*Log[c*
(d + e/Sqrt[x])^n] + 60*b^2*d^6*x^3*Log[c*(d + e/Sqrt[x])^n]^2 - 120*a*b*e^6*n*Log[e + d*Sqrt[x]] + 60*b^2*e^6
*n^2*Log[e + d*Sqrt[x]] - 120*b^2*e^6*n*Log[c*(d + e/Sqrt[x])^n]*Log[e + d*Sqrt[x]] + 60*b^2*e^6*n^2*Log[e + d
*Sqrt[x]]^2 - 120*b^2*e^6*n^2*Log[e + d*Sqrt[x]]*Log[-((d*Sqrt[x])/e)] + 107*b^2*e^6*n^2*Log[x] - 120*b^2*e^6*
n^2*PolyLog[2, 1 + (d*Sqrt[x])/e])/(180*d^6)

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fricas [F]  time = 0.45, size = 0, normalized size = 0.00 \[ {\rm integral}\left (b^{2} x^{2} \log \left (c \left (\frac {d x + e \sqrt {x}}{x}\right )^{n}\right )^{2} + 2 \, a b x^{2} \log \left (c \left (\frac {d x + e \sqrt {x}}{x}\right )^{n}\right ) + a^{2} x^{2}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(a+b*log(c*(d+e/x^(1/2))^n))^2,x, algorithm="fricas")

[Out]

integral(b^2*x^2*log(c*((d*x + e*sqrt(x))/x)^n)^2 + 2*a*b*x^2*log(c*((d*x + e*sqrt(x))/x)^n) + a^2*x^2, x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (b \log \left (c {\left (d + \frac {e}{\sqrt {x}}\right )}^{n}\right ) + a\right )}^{2} x^{2}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(a+b*log(c*(d+e/x^(1/2))^n))^2,x, algorithm="giac")

[Out]

integrate((b*log(c*(d + e/sqrt(x))^n) + a)^2*x^2, x)

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maple [F]  time = 0.10, size = 0, normalized size = 0.00 \[ \int \left (b \ln \left (c \left (d +\frac {e}{\sqrt {x}}\right )^{n}\right )+a \right )^{2} x^{2}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(b*ln(c*(d+e/x^(1/2))^n)+a)^2,x)

[Out]

int(x^2*(b*ln(c*(d+e/x^(1/2))^n)+a)^2,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \frac {1}{3} \, b^{2} n^{2} x^{3} \log \left (d \sqrt {x} + e\right )^{2} - \int -\frac {3 \, {\left (b^{2} d \log \relax (c)^{2} + 2 \, a b d \log \relax (c) + a^{2} d\right )} x^{3} + 3 \, {\left (b^{2} e \log \relax (c)^{2} + 2 \, a b e \log \relax (c) + a^{2} e\right )} x^{\frac {5}{2}} - {\left (b^{2} d n x^{3} - 6 \, {\left (b^{2} d \log \relax (c) + a b d\right )} x^{3} - 6 \, {\left (b^{2} e \log \relax (c) + a b e\right )} x^{\frac {5}{2}} + 6 \, {\left (b^{2} d x^{3} + b^{2} e x^{\frac {5}{2}}\right )} \log \left (x^{\frac {1}{2} \, n}\right )\right )} n \log \left (d \sqrt {x} + e\right ) + 3 \, {\left (b^{2} d x^{3} + b^{2} e x^{\frac {5}{2}}\right )} \log \left (x^{\frac {1}{2} \, n}\right )^{2} - 6 \, {\left ({\left (b^{2} d \log \relax (c) + a b d\right )} x^{3} + {\left (b^{2} e \log \relax (c) + a b e\right )} x^{\frac {5}{2}}\right )} \log \left (x^{\frac {1}{2} \, n}\right )}{3 \, {\left (d x + e \sqrt {x}\right )}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(a+b*log(c*(d+e/x^(1/2))^n))^2,x, algorithm="maxima")

[Out]

1/3*b^2*n^2*x^3*log(d*sqrt(x) + e)^2 - integrate(-1/3*(3*(b^2*d*log(c)^2 + 2*a*b*d*log(c) + a^2*d)*x^3 + 3*(b^
2*e*log(c)^2 + 2*a*b*e*log(c) + a^2*e)*x^(5/2) - (b^2*d*n*x^3 - 6*(b^2*d*log(c) + a*b*d)*x^3 - 6*(b^2*e*log(c)
+ a*b*e)*x^(5/2) + 6*(b^2*d*x^3 + b^2*e*x^(5/2))*log(x^(1/2*n)))*n*log(d*sqrt(x) + e) + 3*(b^2*d*x^3 + b^2*e*
x^(5/2))*log(x^(1/2*n))^2 - 6*((b^2*d*log(c) + a*b*d)*x^3 + (b^2*e*log(c) + a*b*e)*x^(5/2))*log(x^(1/2*n)))/(d
*x + e*sqrt(x)), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int x^2\,{\left (a+b\,\ln \left (c\,{\left (d+\frac {e}{\sqrt {x}}\right )}^n\right )\right )}^2 \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(a + b*log(c*(d + e/x^(1/2))^n))^2,x)

[Out]

int(x^2*(a + b*log(c*(d + e/x^(1/2))^n))^2, x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2*(a+b*ln(c*(d+e/x**(1/2))**n))**2,x)

[Out]

Timed out

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